HOW TO GRAPH A PARABOLA IN INTERCEPT FORM

The axis of symmetry lies halfway between these points, at x = 1.

So, the x-coordinate of the vertex is x = 1 and the y-coordinate of the vertex is :

The graph of the equation is shown below.

Graph : y = (x + 2)(x - 3)

The equation of the parabola is in intercept form

where a = 1, p = -2, and q = 3.

Because a > 0, the parabola opens up.

The x-intercepts occur at (-2, 0) and (3, 0).

The axis of symmetry lies halfway between these points, at x = 0.5.

So, the x-coordinate of the vertex is x = 0.5 and the y-coordinate of the vertex is :

The graph of the equation is shown below.

Graph : y = (x - 4)(x + 2)

The equation of the parabola is in intercept form

where a = 1, p = 4, and q = -2.

Because a > 0, the parabola opens up.

The x-intercepts occur at (4, 0) and (-2, 0).

Halfway of x-intercepts = 4 + (-2) / 2 ==> 1

The axis of symmetry lies halfway between these points, at x = 1.

So, the x-coordinate of the vertex is x = 1 and the y-coordinate of the vertex is :

The graph of the equation is shown below.

graphing-quadratic-with-intercept-q1

Graph : y = -(x - 4)(x + 2)

The equation of the parabola is in intercept form

where a = -1, p = 4, and q = -2.

The x-intercepts occur at (4, 0) and (-2, 0).

Halfway of x-intercepts = 4 + (-2) / 2 ==> 1

The axis of symmetry lies halfway between these points, at x = 1.

So, the x-coordinate of the vertex is x = 1 and the y-coordinate of the vertex is :

The graph of the equation is shown below.

graphing-quadratic-with-intercept-q2.png

Graph : y = 2(x + 3)(x + 5)

The equation of the parabola is in intercept form

where a = 2, p = -3, and q = -5.

Because a > 0, the parabola opens up.

The x-intercepts occur at (-3, 0) and (-5, 0).

Halfway of x-intercepts = (-3) + (-5) / 2 ==> -4

The axis of symmetry lies halfway between these points, at x = -4.

So, the x-coordinate of the vertex is x = -4 and the y-coordinate of the vertex is :

The graph of the equation is shown below.

graphing-quadratic-with-intercept-q3.png

Graph : y = -3x(x + 4)

The equation of the parabola is in intercept form

where a = -3, p = 0, and q = -4.

The x-intercepts occur at (0, 0) and (-4, 0).

Halfway of x-intercepts = 0 + (-4) / 2 ==> -2

The axis of symmetry lies halfway between these points, at x = -2.

So, the x-coordinate of the vertex is x = -2 and the y-coordinate of the vertex is :

Vertex is at (-2, 12)

The graph of the equation is shown below.

graphing-quadratic-with-intercept-q4.png

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